JEE Main2014ChemistryClassification of Elements and Periodicity in PropertiesActual
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species O ²⁻, S ²⁻, N ³⁻, P ³⁻ ?
Options
- AO ²⁻ < N ³⁻ < S ²⁻ < P ³⁻
- BO ²⁻ < P ³⁻ < N ³⁻ < S ²⁻
- CN ^3 < O ²⁻ < P ³⁻ < S ²⁻
- DN ³⁻ < S ²⁻ < O ²⁻ < P ³⁻
Correct answer
A. O ²⁻ < N ³⁻ < S ²⁻ < P ³⁻
Step-by-step solution
For isoelectronic species ionic radii decreases as the charge on ion decreases. Further on moving down in a group ionic radii increases. Hence the correct order is O ²⁻ < N ³⁻ < S ²⁻ < P ³⁻