Which is the correct order of second ionization potential of C, N, O and F in the following ?

Correct answer: B. O>F>N>C The second ionization potential means removal of electron from cation C^ + =1 s^2 2 s^2 2 p^1, ~N^ + =1 s^2 2 s^2 2 p^2 O^ + =1 s^2 2 s^2 2 p^3, ~F^ + =1 s^2 2 s^2 2 p^4 Therefore O>F>N>C

JEE Main 201323 AprilOnline

Exam: JEE Main
Year: 2013
Date: 23 April
Mode: Online
Subject: Chemistry
Chapter: Classification of Elements and Periodicity in Properties

JEE Main 2013 · 23 April · Online · Chemistry · Classification of Elements and Periodicity in Properties

Which is the correct order of second ionization potential of C, N,...

Which is the correct order of second ionization potential of

\mathrm{C}, \mathrm{N}, \mathrm{O}

and

\mathrm{F}

in the following ?

Options

A $\mathrm{O}>\mathrm{N}>\mathrm{F}>\mathrm{C}$
B $\mathrm{O}>\mathrm{F}>\mathrm{N}>\mathrm{C}$
CF $>$ O $>\mathrm{N}>\mathrm{C}$
D $\quad$ C $>$ N $>\mathrm{O}>\mathrm{F}$

Correct answer

B. $\mathrm{O}>\mathrm{F}>\mathrm{N}>\mathrm{C}$

Step-by-step solution

The second ionization potential means removal of electron from cation

\mathrm{C}^{+}=1 s^2 2 s^2 2 p^1, \mathrm{~N}^{+}=1 s^2 2 s^2 2 p^2

\mathrm{O}^{+}=1 s^2 2 s^2 2 p^3, \mathrm{~F}^{+}=1 s^2 2 s^2 2 p^4

Therefore

\mathrm{O}>\mathrm{F}>\mathrm{N}>\mathrm{C}

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