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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

JEE Main 2003 · Chemistry · Classification of Elements and Periodicity in Properties

The radionucleide _ 90 ^ 234 Th undergoes two successive β -decays...

The radionucleide 90234Th{ }_{90}^{234} \mathrm{Th} undergoes two successive β\beta-decays followed by one α\alpha-decay. The atomic number and the mass number respectively of the resulting radionucleide are

Options

  1. A94 and 230
  2. B90 and 230
  3. C92 and 230
  4. D92 and 234

Correct answer

B. 90 and 230

Step-by-step solution

90234Th⟶−β91234X⟶−β92234Th−−α90230Th{ }_{90}^{234} \mathrm{Th} \stackrel{-\beta}{\longrightarrow}{ }_{91}^{234} \mathrm{X} \stackrel{-\beta}{\longrightarrow}{ }_{92}^{234} \mathrm{Th}--\alpha{ }_{90}^{230} \mathrm{Th}
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