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JEE Main20262 April 2026Morning ShiftChemistryCoordination CompoundsActual

Match List - I with List - II. List - I Chromium (III) Complexes (en = ethylene diamine) List - II ₀ (cm ⁻¹ ) A. [Cr(CN)₆]³⁻ I. 15,060 B. [CrF₆]³⁻ II. 17,400 C. [Cr(H₂O)₆]³⁺ III. 22,300 D. [Cr(en)₃]³⁺ IV. 26,600 Choose the correct answer from the options given below :

Options

  1. AA-I, B-II, C-III, D-IV
  2. BA-II, B-III, C-IV, D-I
  3. CA-III, B-IV, C-I, D-II
  4. DA-IV, B-I, C-II, D-III

Correct answer

D. A-IV, B-I, C-II, D-III

Step-by-step solution

The crystal field splitting energy ₀ depends on the strength of the ligand. According to the spectrochemical series, the order of ligand strength is F^- Thus, the order of ₀ for the given complexes is [CrF₆]³⁻ Matching with the given values: [CrF₆]³⁻ has the minimum ₀ = 15,060 cm ⁻¹ (B I). [Cr(H₂O)₆]³⁺ has ₀ = 17,400 cm ⁻¹ (C II). [Cr(en)₃]³⁺ has ₀ = 22,300 cm ⁻¹ (D III). [Cr(CN)₆]³⁻ has the maximum ₀ = 26,600 cm ⁻¹ (A IV). This corresponds to A-IV, B-I, C-II, D-III. Answer: A-IV, B-I, C-II, D-III

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