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JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2026 · 28 January · Morning Shift · Chemistry · Coordination Compounds

The correct statement among the following is:

The correct statement among the following is:

Options

  1. ANi(CO)4\mathrm{Ni}(\mathrm{CO})_{4} and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}arediamagneticand[NiCl4]2−are diamagnetic and \left[\mathrm{NiCl}_{4}\right]^{2-} is paramagnetic.
  2. BNi(CO)4\mathrm{Ni}(\mathrm{CO})_{4} and \left[\mathrm{NiCl}_{4}\right]^{2-}arediamagneticand[Ni(CN)4]2−are diamagnetic and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} is paramagnetic.
  3. C[Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} and [NiCl4]2−\left[\mathrm{NiCl}_{4}\right]^{2-} are diamagnetic and Ni(CO)4\mathrm{Ni}(\mathrm{CO})_{4} is paramagnetic.
  4. DNi(CO)4\mathrm{Ni}(\mathrm{CO})_{4} is diamagnetic and \left[\mathrm{NiCl}_{4}\right]^{2-}and[Ni(CN)4]2−and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} are paramagnetic.

Correct answer

A. Ni(CO)4\mathrm{Ni}(\mathrm{CO})_{4} and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}arediamagneticand[NiCl4]2−are diamagnetic and \left[\mathrm{NiCl}_{4}\right]^{2-} is paramagnetic.

Step-by-step solution

In Ni(CO)4Ni(CO)_4, Nickel is in 00 oxidation state with configuration [Ar]3d84s2[Ar]3d^8 4s^2. COCO is a strong field ligand, causing pairing of 4s4s electrons into 3d3d orbitals, resulting in 3d103d^{10} configuration. It is sp3sp^3 hybridized and diamagnetic (zero unpaired electrons).
In [Ni(CN)4]2−[Ni(CN)_4]^{2-}, Nickel is in +2+2 oxidation state with configuration [Ar]3d8[Ar]3d^8. CN−CN^- is a strong field ligand, causing pairing of the two unpaired electrons in 3d3d orbitals. It is dsp2dsp^2 hybridized (square planar) and diamagnetic.
In [NiCl4]2−[NiCl_4]^{2-}, Nickel is in +2+2 oxidation state with configuration [Ar]3d8[Ar]3d^8. Cl−Cl^- is a weak field ligand and cannot cause pairing of electrons. It has two unpaired electrons in 3d3d orbitals, making it sp3sp^3 hybridized (tetrahedral) and paramagnetic.
Therefore, Ni(CO)4Ni(CO)_4 and [Ni(CN)4]2−[Ni(CN)_4]^{2-} are diamagnetic, while [NiCl4]2−[NiCl_4]^{2-} is paramagnetic.
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