JEE Main 202628 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 28 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Coordination Compounds
JEE Main 2026 · 28 January · Morning Shift · Chemistry · Coordination Compounds
The correct statement among the following is:
The correct statement among the following is:
Options
- A and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} is paramagnetic.
- B and \left[\mathrm{NiCl}_{4}\right]^{2-} is paramagnetic.
- C and are diamagnetic and is paramagnetic.
- D is diamagnetic and \left[\mathrm{NiCl}_{4}\right]^{2-} are paramagnetic.
Correct answer
A. and \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-} is paramagnetic.
Step-by-step solution
In , Nickel is in oxidation state with configuration . is a strong field ligand, causing pairing of electrons into orbitals, resulting in configuration. It is hybridized and diamagnetic (zero unpaired electrons).
In , Nickel is in oxidation state with configuration . is a strong field ligand, causing pairing of the two unpaired electrons in orbitals. It is hybridized (square planar) and diamagnetic.
In , Nickel is in oxidation state with configuration . is a weak field ligand and cannot cause pairing of electrons. It has two unpaired electrons in orbitals, making it hybridized (tetrahedral) and paramagnetic.
Therefore, and are diamagnetic, while is paramagnetic.
In , Nickel is in oxidation state with configuration . is a strong field ligand, causing pairing of the two unpaired electrons in orbitals. It is hybridized (square planar) and diamagnetic.
In , Nickel is in oxidation state with configuration . is a weak field ligand and cannot cause pairing of electrons. It has two unpaired electrons in orbitals, making it hybridized (tetrahedral) and paramagnetic.
Therefore, and are diamagnetic, while is paramagnetic.