JEE Main202624 January 2026Morning ShiftChemistryCoordination CompoundsActual
Given below are two statements: Statement I : The number of paramagnetic species among [ CoF ₆ ]³⁻, [ TiF ₆ ]³⁻ , V ₂ O ₅ and [ Fe ( CN )₆ ]³⁻ is 3. Statement II : K ₄ [ Fe ( CN )₆ ] In the light of the above statements, choose the correct answer from the options given below
Options
- ABoth Statement I and Statement II are true
- BStatement I is false but Statement II is true
- CBoth Statement I and Statement II are false
- DStatement I is true but Statement II is false
Correct answer
A. Both Statement I and Statement II are true
Step-by-step solution
Statement I: Analysis of paramagnetic species. 1. [CoF₆]³⁻ : Co³⁺ is 3d^6 . F^- is a weak field ligand (WFL), so configuration is t_ 2g ^4 e_g^2 . Unpaired electrons ( n ) = 4. Paramagnetic. 2. [TiF₆]³⁻ : Ti³⁺ is 3d^1 . n = 1 . Paramagnetic. 3. V₂O₅ : V⁵⁺ is 3d^0 . n = 0 . Diamagnetic. 4. [Fe(CN)₆]³⁻ : Fe³⁺ is 3d^5 . CN^- is a strong field ligand (SFL), so configuration is t_ 2g ^5 e_g^0 . n = 1 . Paramagnetic. Total paramagnetic species = 3. Statement I is true. Statement II: Analysis of unpaired electrons. 1. K₄[