JEE Main 202623 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 23 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Coordination Compounds
JEE Main 2026 · 23 January · Evening Shift · Chemistry · Coordination Compounds
Identify the CORRECT set of details from the following: A. [Co (NH_...
Identify the CORRECT set of details from the following:
A. \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\mathrm{d}^{2} \mathrm{sp}^{3}\left[\mathrm{MnCl}_{6}\right]^{3-}\mathrm{sp}^{3} \mathrm{~d}^{2}\left[\mathrm{CoF}_{6}\right]^{3-}\mathrm{d}^{2} \mathrm{sp}^{3}\left[\mathrm{FeF}_{6}\right]^{3-}\mathrm{sp}^{3} \mathrm{~d}^{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\mathrm{sp}^{3} hybridized
Choose the correct answer from the options given below:
A. \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\mathrm{d}^{2} \mathrm{sp}^{3}\left[\mathrm{MnCl}_{6}\right]^{3-}\mathrm{sp}^{3} \mathrm{~d}^{2}\left[\mathrm{CoF}_{6}\right]^{3-}\mathrm{d}^{2} \mathrm{sp}^{3}\left[\mathrm{FeF}_{6}\right]^{3-}\mathrm{sp}^{3} \mathrm{~d}^{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\mathrm{sp}^{3} hybridized
Choose the correct answer from the options given below:
Options
- AA, C & E Only
- BA, B & D Only
- CC & D Only
- DA, B, C, D & E
Correct answer
B. A, B & D Only
Step-by-step solution
Analyzing each complex based on Valence Bond Theory (VBT):
A. :
is . is a strong field ligand (SFL) for , causing pairing. This leaves two orbitals vacant. Hybridization is (Inner orbital complex). Statement A is correct.
B. :
is . is a weak field ligand (WFL). No pairing occurs. To accommodate 6 ligands, it uses , , and orbitals. Hybridization is (Outer orbital complex). Statement B is correct.
C. :
is . is a WFL. No pairing occurs. Hybridization is (Outer orbital complex). Statement C is incorrect because it mentions .
D. :
is . is a WFL. No pairing occurs. Hybridization is (Outer orbital complex). Statement D is correct.
E. :
is . is a SFL, causing pairing of the two unpaired electrons in . This leaves one orbital vacant. Hybridization is (Square planar, Inner orbital complex). Statement E is incorrect because it mentions .
Correct statements are A, B, and D.
A. :
is . is a strong field ligand (SFL) for , causing pairing. This leaves two orbitals vacant. Hybridization is (Inner orbital complex). Statement A is correct.
B. :
is . is a weak field ligand (WFL). No pairing occurs. To accommodate 6 ligands, it uses , , and orbitals. Hybridization is (Outer orbital complex). Statement B is correct.
C. :
is . is a WFL. No pairing occurs. Hybridization is (Outer orbital complex). Statement C is incorrect because it mentions .
D. :
is . is a WFL. No pairing occurs. Hybridization is (Outer orbital complex). Statement D is correct.
E. :
is . is a SFL, causing pairing of the two unpaired electrons in . This leaves one orbital vacant. Hybridization is (Square planar, Inner orbital complex). Statement E is incorrect because it mentions .
Correct statements are A, B, and D.