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JEE Main 202623 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
23 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2026 · 23 January · Evening Shift · Chemistry · Coordination Compounds

Identify the CORRECT set of details from the following: A. [Co (NH_...

Identify the CORRECT set of details from the following:
A. \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}:Innerorbitalcomplex;: Inner orbital complex;\mathrm{d}^{2} \mathrm{sp}^{3}hybridized<br>B.hybridized <br> B.\left[\mathrm{MnCl}_{6}\right]^{3-}:Outerorbitalcomplex;: Outer orbital complex;\mathrm{sp}^{3} \mathrm{~d}^{2}hybridized<br>C.hybridized <br> C.\left[\mathrm{CoF}_{6}\right]^{3-}:Outerorbitalcomplex;: Outer orbital complex;\mathrm{d}^{2} \mathrm{sp}^{3}hybridized<br>D.hybridized <br> D.\left[\mathrm{FeF}_{6}\right]^{3-}:Outerorbitalcomplex;: Outer orbital complex;\mathrm{sp}^{3} \mathrm{~d}^{2}hybridized<br>E.hybridized <br> E.\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}:Innerorbitalcomplex;: Inner orbital complex;\mathrm{sp}^{3} hybridized
Choose the correct answer from the options given below:

Options

  1. AA, C & E Only
  2. BA, B & D Only
  3. CC & D Only
  4. DA, B, C, D & E

Correct answer

B. A, B & D Only

Step-by-step solution

Analyzing each complex based on Valence Bond Theory (VBT):
A. [Co(NH3)6]3+[Co(NH_3)_6]^{3+}:
Co3+Co^{3+} is 3d63d^6. NH3NH_3 is a strong field ligand (SFL) for Co3+Co^{3+}, causing pairing. This leaves two 3d3d orbitals vacant. Hybridization is d2sp3d^2sp^3 (Inner orbital complex). Statement A is correct.

B. [MnCl6]3−[MnCl_6]^{3-}:
Mn3+Mn^{3+} is 3d43d^4. Cl−Cl^- is a weak field ligand (WFL). No pairing occurs. To accommodate 6 ligands, it uses 4s4s, 4p4p, and 4d4d orbitals. Hybridization is sp3d2sp^3d^2 (Outer orbital complex). Statement B is correct.

C. [CoF6]3−[CoF_6]^{3-}:
Co3+Co^{3+} is 3d63d^6. F−F^- is a WFL. No pairing occurs. Hybridization is sp3d2sp^3d^2 (Outer orbital complex). Statement C is incorrect because it mentions d2sp3d^2sp^3.

D. [FeF6]3−[FeF_6]^{3-}:
Fe3+Fe^{3+} is 3d53d^5. F−F^- is a WFL. No pairing occurs. Hybridization is sp3d2sp^3d^2 (Outer orbital complex). Statement D is correct.

E. [Ni(CN)4]2−[Ni(CN)_4]^{2-}:
Ni2+Ni^{2+} is 3d83d^8. CN−CN^- is a SFL, causing pairing of the two unpaired electrons in 3d3d. This leaves one 3d3d orbital vacant. Hybridization is dsp2dsp^2 (Square planar, Inner orbital complex). Statement E is incorrect because it mentions sp3sp^3.

Correct statements are A, B, and D.
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