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JEE Main 202529 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2025 · 29 January · Morning Shift · Chemistry · Coordination Compounds

Match List - I with List - II. ( array ll & - I & & - II &...

Match List - I with List - II. (\begin{array}{ll} & \textList - I & & \textList - II \\ & \text{ (Complex) } & & \text{ (Hybridisation & Magnetic characters) } \\ \text{(A)} & \left[\mathrm{MnBr}_4\right]^{2-} & \text{(I)} & d^2 s^3 \text{ & diamagnetic} \\ \text{(B)} & \left[\mathrm{FeF}_6\right]^{3-} & \text{(II)} & \mathrm{sp}^3 \mathrm{ d}^2 \text{ & paramagnetic} \\ \text{(C)} & \left[\mathrm{Co}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-} & \text{(III)} & \mathrm{sp}^3 \text{ & diamagnetic} \\ \text{(D)} & \left[\mathrm{Ni}(\mathrm{CO})_4\right] & \text{(IV)} & \mathrm{sp}^3 \text{ & paramagnetic} \end{array}) Choose the correct answer from the options given below :Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &

Options

  1. A(A) (-(\mathrm{IV}),(\mathrm{B})-(II\mathrm{II}),(\mathrm{C})-(I\mathrm{I}),(\mathrm{D})-(III\mathrm{III}))
  2. B((\mathrm{A})-(III\mathrm{III}),(\mathrm{B})-(I\mathrm{I}),(\mathrm{C})-(II\mathrm{II}),(\mathrm{D})-(\mathrm{IV}))
  3. C(A) (-(\mathrm{IV}),(\mathrm{B})-(I\mathrm{I}),(\mathrm{C})-(II\mathrm{II}),(\mathrm{D})-(III\mathrm{III}))
  4. D((\mathrm{A})-(III\mathrm{III}),(\mathrm{B})-(II\mathrm{II}),(\mathrm{C})-(I\mathrm{I}),(\mathrm{D})-(\mathrm{IV}))

Correct answer

A. (A) (-(\mathrm{IV}),(\mathrm{B})-(II\mathrm{II}),(\mathrm{C})-(I\mathrm{I}),(\mathrm{D})-(III\mathrm{III}))

Step-by-step solution

 (A) [MnBr4]2−Mn+2⇒[Ar]3 d5\begin{aligned} & \text{ (A) }\left[\mathbf{M n B r}_4\right]^{2-} \\ & \mathrm{Mn}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5 \end{aligned} In presence of ligand field Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &
⇒sp3\Rightarrow \mathrm{sp}^3 hybridization, paramagnetic in nature (B) [FeF6]3−Fe+3⇒[Ar]3 d5\left[\mathrm{FeF}_6\right]^{3-}\mathrm{Fe}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5 In presence of ligand field< img src="https://cdn-question-pool.getmarks.app/pyq/jee_main/y10TyOKG-U3RTkeCvMTTLyYSHOIIJiDbtgz8oSi4Qq8.original.fullsize.png">
⇒sp3 d2\Rightarrow \mathrm{sp}^3 \mathrm{~d}^2 hybridization, paramagnetic in nature (C) [Co(C2O4)3]3−Co+3⇒[Ar]3 d6\left[\mathrm{Co}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}\mathrm{Co}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^6 In presence of ligand field Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &
⇒d2sp3\Rightarrow d^2 \mathrm{sp}^3 hybridization, diamagnetic in nature (D) [Ni(CO)4]Ni0⇒[Ar]3 d84 s2\left[\mathrm{Ni}(\mathrm{CO})_4\right]\mathrm{Ni}^0 \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^2 In presence of ligand field Match List - I with List - II. ( array ll & - I & & - II & (Complex) & & (Hybridisation & Magnetic characters) (A) &
⇒sp3\Rightarrow \mathrm{sp}^3 hybridization, diamagnetic in nature
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