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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2025 · 22 January · Morning Shift · Chemistry · Coordination Compounds

From the magnetic behaviour of [NiCl_4]^ 2- (paramagnetic) and...

From the magnetic behaviour of [NiCl4]2−\left[\mathrm{NiCl}_4\right]^{2-} (paramagnetic)and[Ni(CO)4]and \left[\mathrm{Ni}(\mathrm{CO})_4\right] (diamagnetic), choose the correct geometry and oxidation state.

Options

  1. A\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}, tetrahedral \left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}^{\mathrm{II}}, square planar
  2. B[NiCl4]2−\left[\mathrm{NiCl}_4\right]^{2-} : \mathrm{Ni}^{\mathrm{II}}, square planar [Ni(CO)4]:Ni(0)\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0), square planar
  3. C\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}, tetrahedral [Ni(CO)4]:Ni(0)\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0), tetrahedral
  4. D[NiCl4]2−:Ni(0)\left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}(0), tetrahedral [Ni(CO)4]:Ni(0)\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0), square planar

Correct answer

C. \left[\mathrm{NiCl}_4\right]^{2-}: \mathrm{Ni}^{\mathrm{II}}, tetrahedral [Ni(CO)4]:Ni(0)\left[\mathrm{Ni}(\mathrm{CO})_4\right]: \mathrm{Ni}(0), tetrahedral

Step-by-step solution

[NiCl4]2−Ni+2−[Ar]3 d84 s0→sp3\left[\mathrm{NiCl}_4\right]^{2-} \mathrm{Ni}^{+2}-[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^0 \rightarrow \mathrm{sp}^3, Tetrahedral Number of unpaired electron =2=2 paramagentic [Ni(CO)4]Ni(0)→[Ar]3 d104 s0\left[\mathrm{Ni}(\mathrm{CO})_4\right] \mathrm{Ni}(0) \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^0 (After rearrangement) No unpaired electron sp3\mathrm{sp}^3, Tetrahedral, Diamagnetic
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