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From the magnetic behaviour of [ NiCl ₄ ]²⁻ (paramagnetic) and [ Ni ( CO )₄ ] (diamagnetic), choose the correct geometry and oxidation state.

Options

  1. A[ NiCl ₄ ]²⁻: Ni ^ II , tetrahedral [ Ni ( CO )₄ ]: Ni ^ II , square planar
  2. B[ NiCl ₄ ]²⁻ : Ni ^ II , square planar [ Ni ( CO )₄ ]: Ni (0) , square planar
  3. C[ NiCl ₄ ]²⁻: Ni ^ II , tetrahedral [ Ni ( CO )₄ ]: Ni (0) , tetrahedral
  4. D[ NiCl ₄ ]²⁻: Ni (0) , tetrahedral [ Ni ( CO )₄ ]: Ni (0) , square planar

Correct answer

C. [ NiCl ₄ ]²⁻: Ni ^ II , tetrahedral [ Ni ( CO )₄ ]: Ni (0) , tetrahedral

Step-by-step solution

[ NiCl ₄ ]²⁻ Ni ⁺²-[ Ar ] 3 ~d ^8 4 ~s ^0 sp ^3 , Tetrahedral Number of unpaired electron =2 paramagentic [ Ni ( CO )₄ ] Ni (0) [ Ar ] 3 ~d ¹⁰ 4 ~s ^0 (After rearrangement) No unpaired electron sp ^3 , Tetrahedral, Diamagnetic

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