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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Coordination Compounds

JEE Main 2024 · 8 April · Evening Shift · Chemistry · Coordination Compounds

Match List - I with List - II. ( List - I (Complex ion) List - II...

Match List - I with List - II. (
List - I
(Complex ion)		List - II
(Spin only magnetic moment in B.M.)
(A) \left[Cr\left(NH_3\right)_6\right]^{3+}(I) 4.90
(B) \left[NiCl_4\right]^{2-}</td><td>(II) 3.87</td></tr><tr><td>(C) \left[CoF_6\right]^{3-}(III) 0.0
(D) \left[Ni(CN)_4\right]^{2-}(IV) 2.83
) Choose the correct answer from the options given below :

Options

  1. A(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  2. B(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. C(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  4. D(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Correct answer

B. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Step-by-step solution

 (A) [Cr(NH3)6]3+Cr3+:3d3n=3 (unpaired electrons) μ≃3.87 B.M. (II) \begin{aligned} & \text{ (A) }\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+} \\ & \mathrm{Cr}^{3+}: 3 \mathrm{ d}^3 \\ & \mathrm{n}=3 \text{ (unpaired electrons) } \\ & \mu \simeq 3.87 \text{ B.M. (II) } \\ & \end{aligned} (B) [NiCl4]2−Ni2+:3d8n=2μ≃2.83 B.M. (IV) \begin{aligned} & \text{ (B) }\left[\mathrm{NiCl}_4\right]^{2-} \\ & \mathrm{Ni}^{2+}: 3 \mathrm{ d}^8 \\ & \mathrm{n}=2 \\ & \mu \simeq 2.83 \text{ B.M. (IV) } \\ & \end{aligned}  (C) [CoF6]3−Co3+:3d6n=4μ≃4.90 B.M. (I) \begin{aligned} & \text{ (C) }\left[\mathrm{CoF}_6\right]^{3-} \\ & \mathrm{Co}^{3+}: 3 \mathrm{ d}^6 \\ & \mathrm{n}=4 \\ & \mu \simeq 4.90 \text{ B.M. (I) }\end{aligned}  (D) [Ni(CN)4]2−Ni2+:3d8n=0μ=0 B.M. (III) \begin{aligned} & \text{ (D) }\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} \\ & \mathrm{Ni}^{2+}: 3 \mathrm{ d}^8 \\ & \mathrm{n}=0 \\ & \mu=0 \text{ B.M. (III) } \\ & \end{aligned}$SECTION -B
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