Given below are two statements :
Statement (I) : Dimethyl glyoxime forms a six membered covalent chelate when treated with ${NiCl}_{2}$ solution in presence of ${NH}_{4}OH .<br/>Statement (II) : Prussian blue precipitate contains iron both in \left(+ 2\right) and \left(+ 3\right) oxidation states.$

Question

Given below are two statements :
Statement (I) : Dimethyl glyoxime forms a six membered covalent chelate when treated with

{NiCl}_{2}

solution in presence of

{NH}_{4}OH .<br/>Statement (II) : Prussian blue precipitate contains iron both in \left(+ 2\right) and \left(+ 3\right) oxidation states.

Quantrex Academy · Accepted Answer

Correct answer: A. Statement I is false but Statement II is true

According to Statement I,

On addition of dimethylglyoxime (DMG) to nickel ion solution and on adding little bit of ammonia to make solution basic, it will give a red precipitate. This is a very specific test for nickel $+ 2$ cation.

The reaction is as follows,

${Ni}^{2 +} + {NH}_{4}OH + dmg \to$

Given below are two statements : Statement (I) : Dimethyl glyoxime forms a six membered covalent chelate when treated

$2$ hydrogen bonded chelatesare formed.

According to Statement II,

$\begin{array}{ll}III \\ {Fe}_{4}\end{array}$ $\begin{array}{ll}II \\ {\left[Fe{\left(CN\right)}_{6}\right]}_{3}\end{array}$

Prussian Blue

IN this complex Fe is at $+ 3\text{as well as} + 2$ oxidation state. Where ionisation sphere is ${Fe}^{3 +}$ and coordination sphere has ${Fe}^{2 +}$

Hence option A is the answer..

Given below are two statements : Statement (I) : Dimethyl glyoxime...

Options

Correct answer

Step-by-step solution

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