The covalency and oxidation state respectively of boron in [ BF _ 4...

The covalency and oxidation state respectively of boron in

{\left[{BF}_{4}\right]}^{-}

, are

The covalency and oxidation state respectively of boron in [ BF _ 4 ] ^ - , are

Options

A $3$ and $5$
B $3$ and $4$
C $4$ and $4$
D $4$ and $3$

Correct answer

D. $4$ and $3$

Step-by-step solution

The covalency and oxidation state respectively of boron in [ BF _ 4 ] ^ - , are

Number of covalent bond formed by Boron is $4$ .

${\left[{\text{ BF }}_{4}\right]}$ ^{-} $Covalency$ = 4 $The oxidation state of an element represents the charge it would have if all the bonding electrons were assigned to the more electronegative atom in the bond.Oxidation number of fluorine is -1Then,$ B + 4x ( - 1 ) = - 1B - 4 = - 1B = + 3 $Oxidation state$ = + 3 for Boron

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