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The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in Fe H 2 O 6 3 + and Fe CN 6 3 - complexes respectively is:

Options

  1. A6 . 92   B . M . in both
  2. B3 . 87   B . M . and 1 . 732   B . M .
  3. C5 . 92   B . M . and 1 . 732   B . M .
  4. D4 . 89   B . M . and 6 . 92   B . M .

Correct answer

C. 5 . 92   B . M . and 1 . 732   B . M .

Step-by-step solution

The spin only magnetic moment can be calculated as follows μ = n n + 2 BM n = Number of unpaired electrons Fe H 2 O 6 3 + = d 5 ( High   spin   complex ) = 5 .unpaired electrons μ = 5 × 7 = 35 = 5 . 92   B . M . Fe CN 6 3 + = d 5 ( Low   spin   complex ) = 1 μ = 1 × 3 = 3 = 1 . 732   B . M .

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