JEE Main202311 Apr 2023Morning ShiftChemistryCoordination CompoundsActual
The ratio of spin-only magnetic moment values μ eff Cr ( CN ) 6 3 - / μ eff Cr H 2 O 6 3 + is _______
Correct answer
0
Step-by-step solution
In case of Cr 3 + ion , the valence shell electronic configuration is same whether the ligand is strong field or weak field. The spin only magnetic moment , μ eff = n n + 2 BM The valence shell electronic configuration of Cr 3 + is 3 d 3 , hence, it has three unpaired electrons. μ eff  of Cr ( CN ) 6 - 3 = 15  B.M.  μ eff  of Cr H 2 O 6 + 3 = 15  B.M.  Ratio =   1