JEE Main20238 Apr 2023Morning ShiftChemistryCoordination CompoundsActual
The correct order of spin only magnetic moments for the following complex ions is
Options
- AFe ( CN ) 6 3 - < CoF 6 3 - < MnBr 4 2 - < Mn ( CN ) 6 3 -
- BCoF 6 3 - < MnBr 4 2 - < Fe ( CN ) 6 3 - < Mn ( CN ) 6 3 -
- CFe ( CN ) 6 3 - < Mn ( CN ) 6 3 - < CoF 6 3 - < MnBr 4 2 -
- DMnBr 4 2 - < CoF 6 3 - < Fe ( CN ) 6 3 - < Mn ( CN ) 6 3 -
Correct answer
C. Fe ( CN ) 6 3 - < Mn ( CN ) 6 3 - < CoF 6 3 - < MnBr 4 2 -
Step-by-step solution
MnBr 4 2 - is a tetrahedral complex. The electronic configuration Mn 2 + is e 2 t 2 3 and it has 5 unpaired electrons. ∴ μ = 5 ( 5 + 2 ) = 35  B.  M . CoF 6 3 - is an octahedral complex and it is high spin complex. The electronic configuration of Co 3 + is t 2 g 4 e g 2 , it has 4 unpaired electrons ∴ μ = 4 ( 4 + 2 ) = 24  B.M.  Mn ( CN ) 6 3 - is an octahedral complex and it is low spin complex. The electronic configuration Mn 3 + is t 2 g 4 e g 0 it has two unpaired elect