The spin only magnetic moment of [Mn ( H _ 2 O) _ 6 ] ^ 2 +...

A spin-only magnetic moment occurs when an electron rotates on its own axis and generates a magnetic field.

$\mu = \sqrt{n ( n + 2 )}BM$
Here, n is the number of unpaired electrons.
The unit for a spin-only magnetic moment is the Bohr magneton (BM).

$\left({\left[Mn{\left({H}_{2}O\right)}_{6}\right]}^{2 +}\right)</p><p>${Mn}^{2 +} = 3{d}^{5}$</p><p>$\mu = \sqrt{5 ( 5 + 2 )} = 5 . 91BM$