Correct order of spin only magnetic moment of the following complex...

(1) ${\left[{FeF}_{6}\right]}^{3 -}: {Fe}^{3 +} = 3{d}^{5} ( {\Delta}_{O} < P )$

Number of unpaired ${e}^{-} = 5$

$\mu = \sqrt{n ( n + 2 )}BM$

$∴ \mu = \sqrt{35}BM$

(2) ${\left[{CoF}_{6}\right]}^{3 -}: {Co}^{3 +} = 3{d}^{6}\left({\Delta}_{O} < P\right)$

Number of unpaired ${e}^{-} = 4$

$\mu = \sqrt{n ( n + 2 )}BM$

$∴ \mu = \sqrt{24}BM$

(3) ${\left[Co{\left({C}_{2}{O}_{4}\right)}_{3}\right]}^{3 -}: {Co}^{3 +} = 3{d}^{6}\left({\Delta}_{O} > P\right)$

Number of unpaired ${e}^{-} = 0$

$\mu = \sqrt{n ( n + 2 )}BM$

$∴ \mu = 0BM$

So, the correct order is ${\left[{FeF}_{6}\right]}^{3 -} > {\left[{CoF}_{6}\right]}^{3 -} > {\left[Co{\left({C}_{2}{O}_{4}\right)}_{3}\right]}^{3 -}$