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JEE Main202329 Jan 2023Morning ShiftChemistryCoordination CompoundsActual

Chiral complex from the following is : Here en = ethylene diamine

Options

  1. Acis - PtCl 2 ( en ) 2 2 +
  2. Btrans - PtCl 2 ( en ) 2 2 +
  3. Ccis - PtCl 2 NH 3 2
  4. Dtrans - Co NH 3 4 Cl 2 +

Correct answer

A. cis - PtCl 2 ( en ) 2 2 +

Step-by-step solution

Here en = ethylene diamine [PtCl 2 (en) 2 ] 2+ forms cis and trans-isomers. Only the cis-isomers has no element of symmetry. So it is optically active. Trans - [PtCl 2 (en) 2 ] 2+ form is optically inactive. Square planar complexes doesn't exhibit optical isomerism.

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