If Cu H 2 O 4 2 + absorbs a light of wavelength 600   nm for d - d transition, then the value of octahedral crystal field splitting energy for Cu H 2 O 6 2 + will be____ × 10 - 21   J [Nearest integer] (Given : h = 6 . 63 × 10 - 34 Js and c = 3 . 08 × 10 8   ms - 1 )

Step-by-step solution

Δ t = hc λ = 6 . 63 × 10 - 34 × 3 . 08 × 10 8 600 × 10 - 9 = 340 . 34 × 10 - 21   J Δ ∘ = 9 4 Δ t = 9 4 × 340 . 34 × 10 - 21 = 765 . 765 × 10 - 21 ≈ 766 × 10 21   J Note: According to official answer key provided by NTA answer is 745. But according to calculations answer is = 766.