JEE Main202127 Jul 2021Evening ShiftChemistryCoordination CompoundsActual
Given below are two statements : Statement I: Mn ( CN ) 6 3 - , Fe ( CN ) 6 3 - and Co C 2 O 4 3 3 - are d 2 sp 3 hybridised. Statement II : MnCl 6 3 - and FeF 6 3 - are paramagnetic and have 4 and 5 unpaired electrons, respectively. In the light of the above statements, choose the correct answer from the options given below:
Options
- AStatement I is correct but statement II is false
- BBoth statement I and statement II are false
- CStatement I is incorrect but statement II is true
- DBoth statement I and statement II are are true
Correct answer
D. Both statement I and statement II are are true
Step-by-step solution
CN - is strong field ligand. C 2 O 4 2 - is chelating ligand. Mn 3 + has d 4 configuration. Fe 3 + has d 5 configuration. Co 3 + has d 6 configuration. ⇒ All will have larger splitting values hence, they undergo d 2 sp 3 hybridisation. MnCl 6 3 - FeF 6 3 - d 4 configuration, Cl - d 5 configuration, F -