Ti H 2 O 6 3 + absorbs light of wavelength 498 nm during a d - d transition. The octahedral splitting energy for the above complex is _______ × 10 - 19 J . (Round off to the Nearest Integer). h = 6 . 626 × 10 - 34 Js ; c = 3 &#215

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Ti H 2 O 6 3 + absorbs light of wavelength 498 nm during a d - d transition. The octahedral splitting energy for the above complex is _______ &#215; 10 - 19 J . (Round off to the Nearest Integer). h = 6 . 626 &#215; 10 - 34 Js ; c = 3 &#215; 10 8 ms - 1 .

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&#955; absorbed = 498 &#160; nm (given) The octahedral splitting energy &#916; 0 or E = hc &#955; = 0 . 0399 &#215; 10 - 17 &#160; J = 3 . 99 &#215; 10 - 19 &#160; J = 4 . 00 &#215; 10 - 19 &#160; J (round off)

Ti H 2 O 6 3 + absorbs light of wavelength 498 nm during a d - d transition. The octahedral splitting energy for the above complex is _______ × 10 - 19 J . (Round off to the Nearest Integer). h = 6 . 626 × 10 - 34 Js ; c = 3 × 10 8 ms - 1 .

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Ti H 2 O 6 3 + absorbs light of wavelength 498 nm during a d - d transition. The octahedral splitting energy for the above complex is _______ &#215; 10 - 19 J . (Round off to the Nearest Integer). h = 6 . 626 &#215; 10 - 34 Js ; c = 3 &#215; 10 8 ms - 1 .

Correct answer

Step-by-step solution

More from Coordination Compounds

Ti H 2 O 6 3 + absorbs light of wavelength 498 nm during a d - d transition. The octahedral splitting energy for the above complex is _______ × 10 - 19 J . (Round off to the Nearest Integer). h = 6 . 626 × 10 - 34 Js ; c = 3 × 10 8 ms - 1 .