JEE Main20205 Sep 2020Morning ShiftChemistryCoordination CompoundsActual
The values of the crystal field stabilization energies for a high spin d 6 metal ion in octahedral and tetrahedral fields, respectively, are:
Options
- A− 0 .4 Δ o and − 0 . 6 Δ t
- B− 2 .4 Δ o and − 0 . 6   Δ t
- C− 1 .6 Δ o and − 0 . 4 Δ t
- D− 0 .4 Δ o and − 0 .27 Δ t
Correct answer
A. − 0 .4 Δ o and − 0 . 6 Δ t
Step-by-step solution
For d 6 configuration, high spin (i) In case of octahedral complex tg g 2 . 1 . 1 , e g 1 . 1 CFSE = - 0 . 4 nt 2 g + 0 . 6 n eg Δ 0 + n ( P ) = [ - 0 . 4 × 4 + 0 . 6 × 2 ] Δ 0 + 0 = - 0 . 4 Δ 0 (i) In case of tetrahedral complex e 2 , 1 , t 2 1 , 1 , 1 CFSE = - 0 . 6 n e + 0 . 4 nt 2 Δ r = [ - 0 . 6 × 3 + 0 . 4 × 3 ] Δ t = - 0 . 6 Δ t