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JEE Main20203 Sep 2020Evening ShiftChemistryCoordination CompoundsActual

Complex A has a composition of H 12 O 6 Cl 3 C r . If the complex on treatment with conc. H 2 SO 4 loses 13 . 5 % of its original mass, the correct molecular formulas of A is: [Given : atomic mass of C r = 52 amu and C I = 35 amu]

Options

  1. ACr H 2 O 6 Cl 3
  2. BCr H 2 O 3 Cl 3 · 3 H 2 O
  3. CCr H 2 O 5 Cl Cl 2 · H 2 O
  4. DCr H 2 O 4 Cl 2 Cl · 2 H 2 O

Correct answer

D. Cr H 2 O 4 Cl 2 Cl · 2 H 2 O

Step-by-step solution

Conc. H 2 SO 4 acts as dehydrating agent. Molar mass of given complex = 266 . 5   g / mol . On treating with conc. H 2 SO 4 the mass lost by the complex = 13 . 5 100 266 . 5 ≈ 36 g = 2 moles of H 2 O Formula of the complex = Cr H 2 O 4 Cl 2   Cl · 2 H 2 O

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