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JEE Main20203 Sep 2020Evening ShiftChemistryCoordination CompoundsActual

The d-electron configuration of Ru ( en ) 3 Cl 2 , and Fe H 2 O 6 Cl 2 respectively are:

Options

  1. At 2 g 6 e g 0   and   t 2 g 6 e g 0
  2. Bt 2 g 4 e g 2   and   t 2 g 6 e g 0
  3. Ct 2 g 6 e g 0   and   t 2 g 4 e g 2
  4. Dt 2 g 4 e g 2   and   t 2 g 4 e g 2

Correct answer

C. t 2 g 6 e g 0   and   t 2 g 4 e g 2

Step-by-step solution

Ru en 3 Cl 2     ⇒   Ru 2 + = 4 d 6 = t 2 g 6   ,   e g 0 Fe H 2 O 6 2 +   ⇒   Fe 2 + = 3 d 6 = t 2 g 4   ,   e g 2

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