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Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of M + n ion are provided below; their λ max values are marked as A , B and C respectively. The correct match between the complexes and their λ max values is: (i) M ( NCS ) 6 ( - 6 + n ) (ii) MF 6 ( - 6 + n ) (iii) M NH 3 6 n +

Options

  1. AA - ( iii ) ,   ( B ) - ( i ) ,   C - ( ii )
  2. BA - ( ii ) ,   ( B ) - ( i ) ,   C - ( iii )
  3. CA - ( ii ) ,   ( B ) - ( iii ) ,   C - ( i )
  4. D  A - ( i ) ,   ( B ) - ( ii ) ,   C - ( iii )

Correct answer

A. A - ( iii ) ,   ( B ) - ( i ) ,   C - ( ii )

Step-by-step solution

Stronger the ligand greater is splitting of d orbitals and smaller will be wave length of light absorbed. The splitting power of ligands is NH 3 > NCS - > F - So order of wave length of light absorbed is λ NH 3 < λ NC S ¯ < λ F -

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