The correct order of the spin –only magnetic moment of metal ions in the following low-spin complexes, [ V ( C N ) 6 ] 4 - , [ F e ( C N ) 6 ] 4 - , [ R u ( N H 3 ) 6 ] 3 + and [ C r ( N H 3 ) 6 ] 2 + , is:

Step-by-step solution

(i)   V + 2 23 ⟹ A r 3 d 3 4 d 0 ⟹   n = 3 ⇒ μ 3 3 + 2 = 3.87 (ii) C r + 2 24 ⟹ A r 3 d 4 n = 2 ⇒ μ 2 2 + 2 = 2.82 (iii)     R u + 3 44 ⟹ k r 4 d 5   ( n = 1 ) ⇒ μ 1 1 + 2 = 3 (iv)     F e + 2 26   ⟹ A r 3 d 6   ( n = 0 ) ⇒ μ = 0 Order of magnetic moment will be ∝ no. of unpaired e - V + 2 >   C r + 2 > R u + 3   > F e + 2 μ = n ( n + 2 ) B.M. Hence more the va