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JEE Main201912 Jan 2019Evening ShiftChemistryCoordination CompoundsActual

The magnetic moment of an octahedral homoleptic Mn ( II ) complex is 5 .9   B . M . . The suitable ligand for this complex is:

Options

  1. AC N -
  2. BC O
  3. CEthylenediamine
  4. DN C S -

Correct answer

D. N C S -

Step-by-step solution

M n 2 + will have configuration = 3 d 5 4 s 0 μ = 5.93 = n n + 2 or, n = 5 as 35 = 5.93 If has 5 unpaired electron which are not getting paired up. This implies that the ligand paired up, and the ligand is a weak field ligand. Among the given options, weak ligand is N C S -

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