JEE Main201912 Jan 2019Morning ShiftChemistryCoordination CompoundsActual
The metal's d - orbitals that are directly facing the ligands in K 3 C o C N 6 are:
Options
- Ad x y , d x z and d y z
- Bd x 2 - y 2 and d z 2
- Cd x y and d x 2 - y 2
- Dd x z , d y z and d z 2
Correct answer
B. d x 2 - y 2 and d z 2
Step-by-step solution
Give K 3 [ C o C N 6 ] is inner orbital complex with hybridization d 2 s p 3 and octahedral geometry. Ligands are approaching metal along the axes. Hence d x 2 - y 2 , d z 2 orbitals are directly in front of the ligands.