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JEE Main201910 Jan 2019Evening ShiftChemistryCoordination CompoundsActual

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:

Options

  1. AFe 2 +
  2. BCo 2 +
  3. CNi 2 +
  4. DMn 2 +

Correct answer

B. Co 2 +

Step-by-step solution

The electronic configuration for Co 2 + z = 27 = 4 s 0 3 d 7   When it combines with weak ligands (high spin complex), t 2 g 2 ,2 , 1   eg 1 ,1 , it has 3 unpaired electrons, whereas when it bonds with strong ligands (low spin complex), t 2 g 2 ,2 , 2   eg 1 ,0 , then, it has 1 unpaired electron. The difference in number of unpaired electrons is equal to two.

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