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On treatment of 100 mL of 0 . 1 M solution of CoCl 3 . 6 H 2 O with excess AgNO 3 ; 1 .2 × 10 22 ions are precipitated. The complex is:

Options

  1. ACo H 2 O 3 Cl 3 . 3 H 2 O
  2. BCo H 2 O 6 Cl 3
  3. CCo H 2 O 5 Cl Cl 2 .   H 2 O
  4. DCo H 2 O 4 Cl 2 Cl . 2 H 2 O

Correct answer

C. Co H 2 O 5 Cl Cl 2 .   H 2 O

Step-by-step solution

Moles of CoCl 3 . 6 H 2 O = 100 × 0 . 1 × 10 - 3 = 10 - 2 mole Moles of Cl - ions precipitated = 1 . 2 × 10 22 6 × 10 23 = 2 × 10 - 2   mole So, one mole of complex will release two moles of chloride ions so, formula of complex is Co H 2 O 5 Cl Cl 2 .   H 2 O

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