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JEE Main2016ChemistryCoordination CompoundsActual

The pair having the same magnetic moment is: A t . N o . : C r = 24 , M n = 25 , F e = 26 , C o = 27

Options

  1. AM n H 2 O 6 2 + a n d C r H 2 O 6 2 +
  2. BC o C l 4 2 - a n d F e H 2 O 6 2 +
  3. CC r H 2 O 6 2 + a n d C o C l 4 2 -
  4. DC r H 2 O 6 2 + a n d F e H 2 O 6 2 +

Correct answer

D. C r H 2 O 6 2 + a n d F e H 2 O 6 2 +

Step-by-step solution

The compounds having the same number of unpaired electrons will have same magnetic moment. Magnetic moment μ   =   n n + 2 where n is the number of unpaired electrons [ C r ( H 2 O ) 6 ] + 2 C r 2+ . ( 3 d 4 )   with weak field ligand so unpaired electrons are 4 So, μ =   4 4 + 2   =   24 F e + 2 ( 3 d 6 ) Weak field ligand so unpaired electrons are 4 μ   =   4 4 + 2   =   24

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