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A solution containing 2.675 ~g of CoCl ₃ .6 NH ₃ (molar mass =267.5 ~g ~mol ⁻¹ ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO ₃ to give 4.78 ~g of AgCl (molar mass =143.5 ~g ~mol ⁻¹ ). The formula of the complex is (At. Mass of Ag =108 u )

Options

  1. A[ Co ( NH ₃ )₆ ] Cl ₃
  2. B[ CoCl ₂ ( NH ₃ )₄ ] Cl
  3. C[ CoCl ₃ ( NH ₃ )₃ ]
  4. D[ CoCl ( NH ₃ )₅ ] Cl ₂

Correct answer

A. [ Co ( NH ₃ )₆ ] Cl ₃

Step-by-step solution

CoCl ₃ .6 NH ₃ Cl ⁻ AgNO ₃ AgCl n ( AgCl )= x ( CoCl ₃ .6 NH ₃ ) 4.78 143.5 = 2.675 267.5 x =3 The complex is [ Co ( NH ₃ )₆ ] Cl ₃

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