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JEE Main 20262 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
2 April
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2026 · 2 April · Morning Shift · Chemistry · d and f Block Elements

Which of the following sets includes all the species that will...

Which of the following sets includes all the species that will change the orange colour of K2Cr2O7K_2Cr_2O_7 in acidic medium?

Options

  1. AFe2+,Sn2+,I−,S2−Fe^{2+}, Sn^{2+}, I^-, S^{2-}
  2. BS2−,Fe3+,I−,C2O42−S^{2-}, Fe^{3+}, I^-, C_2O_4^{2-}
  3. CFe2+,NO2−,SO2,Sn4+Fe^{2+}, NO_2^-, SO_2, Sn^{4+}
  4. DFe3+,SO42−,S2−,Sn4+Fe^{3+}, SO_4^{2-}, S^{2-}, Sn^{4+}

Correct answer

A. Fe2+,Sn2+,I−,S2−Fe^{2+}, Sn^{2+}, I^-, S^{2-}

Step-by-step solution

K2Cr2O7K_2Cr_2O_7 in acidic medium acts as a strong oxidizing agent. It changes its colour from orange (Cr2O72−Cr_2O_7^{2-}) to green (Cr3+Cr^{3+}) when it reacts with a reducing agent.

We need to identify the set in which all species can act as reducing agents (i.e., they can be oxidized to a higher oxidation state).

In option (A), Fe2+Fe^{2+} oxidizes to Fe3+Fe^{3+}, Sn2+Sn^{2+} oxidizes to Sn4+Sn^{4+}, I−I^- oxidizes to I2I_2, and S2−S^{2-} oxidizes to SS. All of these are reducing agents.

In option (B), Fe3+Fe^{3+} is already in its maximum stable oxidation state and cannot be oxidized further.

In option (C), Sn4+Sn^{4+} cannot be oxidized further.

In option (D), Fe3+Fe^{3+}, SO42−SO_4^{2-}, and Sn4+Sn^{4+} cannot be oxidized further.

Thus, only the species in option (A) will change the orange colour of K2Cr2O7K_2Cr_2O_7.

Answer: Fe2+,Sn2+,I−,S2−Fe^{2+}, Sn^{2+}, I^-, S^{2-}
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