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JEE Main 202429 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2024 · 29 January · Morning Shift · Chemistry · d and f Block Elements

In chromyl chloride test for confirmation of Cl ^ – ion, a yellow...

In chromyl chloride test for confirmation of Cl–{Cl}^{–} ion, a yellow solution is obtained. Acidification of the solution and addition of amyl alcohol and 1010 % {H}_{2}{O}_{2}turns organic layer blue indicating formation of chromium pentoxide. The oxidation state of chromium in that isIn chromyl chloride test for confirmation of Cl ^ – ion, a yellow solution is obtained. Acidification of the solution

Options

  1. A+6+ 6
  2. B+5+ 5
  3. C+10+ 10
  4. D+3+ 3

Correct answer

A. +6+ 6

Step-by-step solution

The chromyl chloride test is used to detect chloride ions in the qualitative analysis. If any chloride salt like sodium chloride is heated with acidified potassium dichromate it produces red colour fumes of chromyl chloride. It confirms the presence of chloride ions in that salt.

Cl−+K2Cr2O7+H2SO4→CrO2Cl2→Basic mediumCrO42−yellow solution+Cl−{Cl}^{-} + {K}_{2}{Cr}_{2}{O}_{7} + {H}_{2}{SO}_{4} \to {CrO}_{2}{Cl}_{2}\overset{\text{Basic medium}}{\to}\mathop{{CrO}_{4}^{2 -}}_{\text{yellow solution}} + {Cl}^{-}

Chromate reacts rapidly with hydrogen peroxide to exchange two oxo ligands and become diperoxochromate(VI)

CrO42−yellowsolution→3.10\mathop{{CrO}_{4}^{2 -}}_{yellowsolution}\to 3 . 10 % {H}_{2}{O}_{2}1.Acidification2.Amylalcohol\begin{array}{ll}1 . Acidification \\ 2 . Amylalcohol\end{array}CrO5bluecompound\mathop{{CrO}_{5}}_{bluecompound}

In chromyl chloride test for confirmation of Cl ^ – ion, a yellow solution is obtained. Acidification of the solution

Hence, the answer is option A.

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