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JEE Main 202310 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2023 · 10 April · Morning Shift · Chemistry · d and f Block Elements

Which of the following statements are correct? (A) The M ^ 3 + / M...

Which of the following statements are correct?

(A) The M3+/M2+{M}^{3 +} / {M}^{2 +} reduction potential for iron is greater than manganese.

(B) The higher oxidation states of first row d-block elements get stabilized by oxide ion

(C) Aqueous solution of Cr2+{Cr}^{2 +} can liberate hydrogen from dilute acid

(D) Magnetic moment of V2+{V}^{2 +} is observed between 4.4−5.2BM4 . 4 - 5 . 2BM

Choose the correct answer from the options given below:

Options

  1. A\left(B\right), (C)\left(C\right) only
  2. B(A),\left(A\right),\left(B\right), (D)\left(D\right) only
  3. C\left(C\right), (D)\left(D\right) only
  4. D\left(A\right), (B)\left(B\right) only

Correct answer

A. \left(B\right), (C)\left(C\right) only

Step-by-step solution

The valence electronic configuration of Mn3+{Mn}^{3 +} is 3d43{d}^{4} and that of Mn2+{Mn}^{2 +} is stable 3d53{d}^{5}.The valence electronic configuration of Fe3+{Fe}^{3 +} is 3d53{d}^{5} and that of Fe2+{Fe}^{2 +} is 3d63{d}^{6}.

The reduction electrode potential of Mn3+/Mn2+{Mn}^{3 +} / {Mn}^{2 +} is +1.57V+ 1 . 57V while that of Fe3+/Fe2+{Fe}^{3 +} / {Fe}^{2 +} is +0.77V+ 0 . 77V, hence A is wrong. Higher oxidation state of smaller dd-block elements is stabilised (or say form compounds) with smaller anion oxide that can be explained by stearic reason hence BB is correct.

The oxidation electrode potential of Cr2+/Cr3+{Cr}^{2 +} / {Cr}^{3 +} is +0.41V+ 0 . 41V hence, it can reduce H+{H}^{+} and so liberate H2{H}_{2}.

The unpaired electrons in V2+{V}^{2 +} are 33 hence, the magnetic moment of V2+{V}^{2 +} will be lesser than 4.4BM4 . 4BM.

Hence, only BB and CC are correct.

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