In chromyl chloride, the number of d-electrons present on chromium...

In chromyl chloride (${CrO}_{2}{Cl}_{2}$), the oxidation state of chromium $( Cr )$ is $+ 6 .$

So, $Cr ( VI ) = [ Ar{]}^{18}3{d}^{0}$

For the given elements the configuration is,$Mn ( VII ) = [ Ar{]}^{18}3{d}^{0}$

$Fe ( III ) = [ Ar{]}^{18}3{d}^{5}$

$Ti ( III ) = [ Ar{]}^{18}3{d}^{1}$

$V ( IV ) = [ Ar{]}^{18}3{d}^{1}$

So among the given options $Mn ( VII )$ and $Cr ( VI )$ will have same number of d-electrons.