99 Percentile Qs Bank for JEE MainChemistryClassification of Elements and Periodicity in Properties
The amount of energy released when 10 12 atoms of Cl vapours are converted into Cl - ions according to the equation Cl   g + e - ⟶ Cl -   g is 58 × 10 - 10   J . Calculate Δ eg H - of Cl atom in kJ   mol - 1 or eV   atom - 1 .
Options
- A- 0 . 036   eV   atom - 1
- B- 3 . 48   eV   atom - 1
- C- 0 . 038   eV   atom - 1
- D- 0 . 361   eV   atom - 1
Correct answer
A. - 0 . 036   eV   atom - 1
Step-by-step solution
Given: The amount of energy released when 10 12 atoms of Cl vapours are converted into Cl - ions = 58 × 10 - 10   J The amount of energy released when 1   mol ( ≈ 6 . 0 × 10 23 atoms) of Cl are converted into Cl - ions according to the above equation is Δ cg H - of Cl vapours. ∴   Δ eg H - of Cl vapours = - 58 × 10 - 10   J × 6 × 10 23 10 12 = - 348 × 10   J   mol - 1 = - 3 . 48   kJ   mol - 1 We know that 1   eV