The electron gain enthalpy Δ eg H of Cl ( g ) is - 349   kJ   mol - 1 . If the ground state energy of Cl ( g ) is x   kJ   mol - 1 , the ground state energy in   kJ   mol - 1 of Cl - ( g ) is

Step-by-step solution

C l 2 → ∆ e g H   2 C l - +   2 e - As ground state energy is   x   k J   m o l e - 1 , x = ∆ E g r o u n d   s t a t e   -   ∆ e g H ∆ E g r o u n d   s t a t e = x + ∆ e g H ∆ E g r o u n d   s t a t e = x - 349