99 Percentile Qs Bank for JEE MainChemistryClassification of Elements and Periodicity in Properties
Value of shielding constant σ for Ne is 4 . 15 . Find the effective nuclear charge on Na + and F - , respectively.
Options
- A4 . 85 ,   6 . 85
- B5 . 85 ,   6 . 85
- C6 . 85 ,   4 . 85
- D4 . 85 ,   4 . 85
Correct answer
C. 6 . 85 ,   4 . 85
Step-by-step solution
Ne ,   Na + ,   Fe - are all isoelectronic species.. Electronic configuration of each species is given as Ne 10 :   1 s 2 ,   2 s 2 2 p 6 Na + 11 :   1 s 2 ,   2 s 2 2 p 6 F - 9 :   1 s 2 ,   2 s 2 2 p 6 All have shielding constant. Also, Z e f f   = Z - σ ∴   Z eff   Na +   = 11 - 4 . 15 = 6 . 85 and Z eff F - = 9 - 4 . 15 = 4 . 85