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The magnetic moment of the high spin complex is 5 . 92   BM . What is the electronic configuration?

Options

  1. At 2 g 3 eg 1
  2. Bt 2 g 4 eg 2
  3. Ct 2 g 3 eg 2
  4. Dt 2 g 5 eg 0

Correct answer

C. t 2 g 3 eg 2

Step-by-step solution

Magnetic moment, μ = n n + 2   = 5 . 92 BM Hence, number of unpaired electrons, n = 5 As the complex mentioned is high spin, electronic configuration should be t 2 g 3 e g 2 . As no pairing of electrons takes place against hund's rule, pairing energy > ∆ o

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