99 Percentile Qs Bank for JEE MainChemistryCoordination Compounds
The ₀ of a coordination complex of a metal ion (3 d^1 ) is 1000 ~kJ ~mol ⁻¹ . If the energy of t_ 2 g orbitals is -400 ~kJ ~mol ⁻¹ , the energy (in kJ mol ⁻¹ ) of e_g orbitals is
Options
- A-600
- B600
- C1000
- D400
Correct answer
B. 600
Step-by-step solution
Given, ₀ for (3 d^1 ) : ₀=1000 ~kJ ~mol ⁻¹ Energy of (t_ 2 g ) , i.e. E (t_ 2 g ) . aligned E (t_ 2 g ) & =-400 ~kJ ~mol ⁻¹ ₀ & =E_ (e_g ) -E (t_ 2 g ) aligned (Energy difference) (Higher energy) (Lower energy) where, E_ (e_g ) is the energy of orbitals. Therefore, or, aligned & 1000=E_ (e_g ) -(-400) & 1000=E_ (e_g ) +400 & E_ (e_g ) =1000-400 & E_ (e_g ) =600 ~kJ / mol aligned Hence, option (b) is the correct answer.