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99 Percentile Qs Bank for JEE MainChemistryCoordination Compounds

Consider the complexes. (i) [ Pd ( NH ₃ )₂ ClBr ] (ii) [ Pd ( NH ₃ )₂ Cl ₂ ] (iii) [ Pd ( en ) Cl ₂ ] (iv) [Pd(en) ClBr ] (v) [ Pd ( en )₂ ] Cl ₂ (en = ethylenediamine) The total number of geometrical isomers of (A) is same as the total number of geometrical isomers of

Options

  1. A(ii)
  2. B(iii)
  3. C(iv)
  4. D(v)

Correct answer

A. (ii)

Step-by-step solution

(i) [ Pd ( NH ₃ )₂ ClBr ] (ii) [ Pd ( NH ₃ )₂ Cl ₂ ]M a₂ b cM a₂ b₂ G.I =2 G.I =2 cis and trans cis and trans (iii) [ Pd ( en ) Cl ₂ ] (iv) [ Pd ( en ) ClBr ] Maab ₂M a b c G . I =3 G.I =3 (v) Pd ( en )₂ Cl ₂ Ma ₂ ~b ₂ G . I =4 So, only (i) and (ii) have two, i.e. same number of geometrical isomers.

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