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[Cr(H 2 O) 6 ]Cl 3 (At. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is

Options

  1. A3 d xy 1 , 3 d xz 1 , 3 d z 2 1
  2. B3 d x 2 - y 2 , 3 d z 2 1 , 3 d xz 1
  3. C3 d xy 1 , 3 d x 2 - y 2 1 , 3 d yz 1
  4. D3 d xy 1 , 3 d yz 1 , 3 d xz 1

Correct answer

D. 3 d xy 1 , 3 d yz 1 , 3 d xz 1

Step-by-step solution

Magnetic moment = n n + 2 3 . 3 8 = n n + 2   or,   3 . 8 3 2 = n n + 2 or, 14.6689 = n 2 + 2n On solving the equation, n = 3 Cr 3 + → [Ar] 3d 3

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