99 Percentile Qs Bank for JEE MainChemistryCoordination Compounds
In C O H 2 O 6 2 + , there are three unpaired electrons present. The μ c a l c u l a t e d is 3.87 BM which is quite different from the μ e x p e r i m e n t a l of 4.40 BM. This is because of
Options
- AIncrease n number of unpaired electrons
- BSome contribution of the orbital motion of the electron to the magnetic moment
- CChange in orbital spin of the electron
- Dd-d transition
Correct answer
B. Some contribution of the orbital motion of the electron to the magnetic moment
Step-by-step solution
In C o H 2 O 6 2 + , there are three unpaired electrons present as, μ c a l =   n n + 1 B M =   3 3 + 1 B M = 3.87   B M As, the t 2 g orbital is unsymmetrically filled hence due to orbital motion contribution, magnetic moment goes with the value 4.40 BM