99 Percentile Qs Bank for JEE MainChemistryCoordination Compounds
The hybridisation of metals involved in the following complexes, respectively are [ Mn ( CN )₆ ]³⁻, [ CoF ₆ ]³⁻
Options
- As p^3 d^2, s p^3 d^2
- Bs p^3 d^2, d^2 s p^3
- Cd^2 s p^3, d^2 s p^3
- Dd^2 s p^3, s p^3 d^2
Correct answer
D. d^2 s p^3, s p^3 d^2
Step-by-step solution
In [ Mn ( CN )₆ ]³⁻, Mn is in +3 oxidation state. As CN ⁻ is a strong field ligand, it causes pairing of two 3 d electrons, thereby making two d -orbitals vacant, namely d_ x^2-y^2 and d_ z^2 . These two d -orbitals and one 4 s and three 4 p -orbitals hybridise and give d^2 s p^3 -hybridisation. In [ Co ( F )₆ ]³⁻, Co is in +3 oxidation state. As F ⁻ is a weak field ligand, so it cannot cause the pairing of unpaired 3 d -electrons. Thus, one 4 s , three 4 p -orbitals and two 4 d -orbitals hybridise and give s p^3 d