Diborane reacts with ammonia under different conditions to give a...

Diborane reacts with ammonia under different conditions to give a variety of products. Which one among the following is not formed in these reactions?

Options

A $\mathrm{B}_2 \mathrm{H}_6 \cdot 2 \mathrm{NH}_3$
B $\mathrm{B}_{12} \mathrm{H}_{12}$
C $\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6$
D $(\mathrm{BN})_n$

Correct answer

B. $\mathrm{B}_{12} \mathrm{H}_{12}$

Step-by-step solution

Diborane reacts with ammonia and gives different products under different reaction conditions as

\mathrm{B}_2 \mathrm{H}_6+\underset{\text { (excess) }}{\mathrm{NH}_3} \underset{\text { temperature }}{\stackrel{\text { at low }}{\longrightarrow}}\underset{\text {addition product} }{\mathrm{B}_2 \mathrm{H}_6 \cdot 2 \mathrm{NH}_3}\mathrm{B}_2 \mathrm{H}_6+\underset{\text { (excess) }}{\mathrm{NH}_3} \stackrel{\text { high temperature }}{\longrightarrow}\underset{\text {boron nitride (resembles with graphite) }}{(\mathrm{BN})_n}\underset{1}{\mathrm{~B}_2 \mathrm{H}_6}\underset{:}{+}\underset{2}{\mathrm{NH}_3 }\stackrel{\text { high temperature }}{\longrightarrow}\underset{\text {borazine (inorganic benzene)}}{\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6}

Thus,

\mathrm{B}_{12} \mathrm{H}_{12}

is not the product of reaction between diborane and ammonia.

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