Determine the dimensions of Planck's constant h using the equation E = h , where E represents the energy and represents the frequency.

Correct answer: A. [ML^2 T^ -1 ] Given equation is E = h . The dimensional formula for energy E is [ML^2 T^ -2 ] . The dimensional formula for frequency is [T^ -1 ] . Rearranging the equation for Planck's constant h , we get h = (E)/( ) . Substituting the dimensions, we get [h] = [ML^2 T^ -2 ] [T^ -1 ] = [ML^2 T^ -1 ] .

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Determine the dimensions of Planck's constant h using the equation...

Determine the dimensions of Planck's constant

h

using the equation

E = h\nu

, where

E

represents the energy and

\nu

represents the frequency.

Options

A $[ML^2 T^{-1}]$
B $[ML^2 T^{-3}]$
C $[ML T^{-1}]$
D $[ML^2 T^{-2}]$

Correct answer

A. $[ML^2 T^{-1}]$

Step-by-step solution

Given equation is

E = h\nu

.

The dimensional formula for energy

E

[ML^2 T^{-2}]

.

The dimensional formula for frequency

\nu

[T^{-1}]

.

Rearranging the equation for Planck's constant

h

, we get

h = \dfrac{E}{\nu}

.

Substituting the dimensions, we get

[h] = \dfrac{[ML^2 T^{-2}]}{[T^{-1}]} = [ML^2 T^{-1}]

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