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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Assuming force, length, and time to be the fundamental quantities,...

Assuming force, length, and time to be the fundamental quantities, determine the dimensions of density.

Options

  1. AFL−3T2FL^{-3} T^2
  2. BFL−4T2FL^{-4} T^2
  3. CF2L−4T2F^2L^{-4} T^2
  4. DFL−2T2FL^{-2} T^2

Correct answer

B. FL−4T2FL^{-4} T^2

Step-by-step solution

Density is defined as mass per unit volume.

Density =MV=ML3= \dfrac{M}{V} = \dfrac{M}{L^3}

From Newton's second law, force is the product of mass and acceleration.

F=M×A=M×LT−2F = M \times A = M \times LT^{-2}

M=FL−1T2M = FL^{-1}T^2

Substituting the dimensions of mass in the expression for density:

Density =FL−1T2L3=FL−4T2= \dfrac{FL^{-1}T^2}{L^3} = FL^{-4}T^2
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