Assume the acceleration due to gravity at a certain location is 10 m/s^2 . Determine its value in cm/(minute)^2 .

Correct answer: D. 3.6 × 10^6 Given g = 10 m/s^2 . To convert the unit from m/s^2 to cm/min^2 , we use the conversions 1 m = 100 cm and 1 s = (1)/(60) min . Substituting these into the given value: g = 10 × 100 cm ((1)/(60) min)^2 g = 10 × 100 × (60)^2 cm/min^2 g = 1000 × 3600 cm/min^2 g = 3.6 × 10^6 cm/min^2

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Assume the acceleration due to gravity at a certain location is 10...

Assume the acceleration due to gravity at a certain location is

10 \text{ m/s}^2

. Determine its value in

\text{cm/(minute)}^2

Options

A $3.6 \times 10^4$
B $6.0 \times 10^4$
C $3.6 \times 10^5$
D $3.6 \times 10^6$

Correct answer

D. $3.6 \times 10^6$

Step-by-step solution

Given

g = 10 \text{ m/s}^2

.

To convert the unit from

\text{m/s}^2

\text{cm/min}^2

, we use the conversions

1 \text{ m} = 100 \text{ cm}

and

1 \text{ s} = \dfrac{1}{60} \text{ min}

.

Substituting these into the given value:

g = 10 \times \dfrac{100 \text{ cm}}{\left(\dfrac{1}{60} \text{ min}\right)^2}

g = 10 \times 100 \times (60)^2 \text{ cm/min}^2

g = 1000 \times 3600 \text{ cm/min}^2

g = 3.6 \times 10^6 \text{ cm/min}^2

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