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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

The average speed of a snail is 0.020 miles/hour, whereas that of a...

The average speed of a snail is 0.0200.020 miles/hour, whereas that of a leopard is 7070 miles/hour. Determine these speeds in SI units.

Options

  1. A0.89 m/s0.89 \text{ m/s}, 310 m/s310 \text{ m/s}
  2. B0.0055 m/s0.0055 \text{ m/s}, 19 m/s19 \text{ m/s}
  3. C0.032 m/s0.032 \text{ m/s}, 112 m/s112 \text{ m/s}
  4. D0.0089 m/s0.0089 \text{ m/s}, 31 m/s31 \text{ m/s}

Correct answer

D. 0.0089 m/s0.0089 \text{ m/s}, 31 m/s31 \text{ m/s}

Step-by-step solution

The SI unit of speed is m/s\text{m/s}.

We know that 1 mile≈1609 m1 \text{ mile} \approx 1609 \text{ m} and 1 hour=3600 s1 \text{ hour} = 3600 \text{ s}.

The conversion factor from miles/hour\text{miles/hour} to m/s\text{m/s} is 16093600≈0.447 m/s\dfrac{1609}{3600} \approx 0.447 \text{ m/s}.

Speed of the snail =0.020 miles/hour=0.020×0.447 m/s≈0.0089 m/s= 0.020 \text{ miles/hour} = 0.020 \times 0.447 \text{ m/s} \approx 0.0089 \text{ m/s}.

Speed of the leopard =70 miles/hour=70×0.447 m/s≈31 m/s= 70 \text{ miles/hour} = 70 \times 0.447 \text{ m/s} \approx 31 \text{ m/s}.
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